| M | A | T | H |
| 2 | 1 | B |
Problem: Show that all Pascal matrices like
1 1 1 1 1
1 2 3 4 5
1 3 6 10 15
1 4 10 20 35
1 5 15 35 70
have determinant 1. You get the pascal triangle, if you rotate the matrix by 45 degrees.
You can generate the matrix as follows:
A[n_]:=Table[Binomial[k+l-2,l-1],{k,n},{l,n}];
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Here is an other type of matrices which could be called Pascal triangle matrices.
Also they have determinant 1, but because of much simpler reasons.
1 0 0 0 0
1 1 0 0 0
1 2 1 0 0
1 3 3 1 0
1 4 6 4 1
A cool way to generate it is to write it as the matrix exponential exp(B) = 1+B+B^2/2! + ...
of a simpler matrix.
A[n_]:=Table[If[i-j==1,i-1,0],{i,n},{j,n}]; MatrixExp[A[5]]
Please send questions and comments to math21b@fas.harvard.edu
Math21b (Exam Group 1)| Oliver Knill | Spring 2009 |
Department of Mathematics |
Faculty of Art and Sciences |
Harvard University
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