The Boolean-Green function problem

Inverse Boolean Matrix In unit 6, you explored the question whether the inverse of an invertible n x n matrix with entries 0 or 1 always has entries 0,1,-1 (as in the case n=2. The answer is already ``no" in the case n=3, but only in the case n=4 is it possible that the maximal entry is larger than 1, like 2. Matrices with entries 0 or 1 are also called Boolean matrices. They are of great interest in mathematics. Now, we can ask:
How large can A-1ij get if A is an invertible nxn Boolean matrix?
I call it the Boolean Green function problem. In principle, we can look over the entire set of all 0-1 matrices, but that set is getting large pretty quickly. It can still just be done for n=5, where we have 225=33554432 matrices (this is the last value, where I could get through all cases and confirm the maximum). For n=6, we would have to run through 236 = 68719476736 matrices already. Anyway, here is the code to check it all. Try to change 3 to 7 and see your laptop burn! You would need Thousands of TBytes of Ram just to evaluate Boolean[7] which consists of 562'949'953'421'312 matrices.

Boolean[n_]:=Tuples[{0,1},{n,n}]; 
F[n_]:=Module[{B=Boolean[n]},
Max[Table[If[Det[B[[k]]]!=0,
   Max[Flatten[Inverse[B[[k]]]]],0],
    {k,Length[B]}]]];
F[3] 

Monte Carlo tests

For n=20 already, we have 2400 ∼ 10120 possibilities. There are about 1080 elementary particles in the observable universe so that this is not an option even if each particle would have computed a zillion of case each second since the big bang (1017 seconds in the past). But we can explore using Monte-Carlo tests, producing random matrices and see how large values we can get by probing the large space. This might well miss the actual maximum as the maxima become needles in a haystack but probing the space randomly could give us an idea about the growth:

RandomInvertibleBooleanMatrix[n_]:=Module[{A,found=False},
  While[Not[found],A=Table[Random[Integer,1],{n},{n}];
                    found=(Det[A]!=0)];A];
FindExtrema[n_,tries_]:=Module[{max=1,min=1,M,m},
  Do[A=RandomInvertibleBooleanMatrix[n];
     M=Max[Flatten[Inverse[A]]]; If[M>max,max=M; Print[max]];
     m=Min[Flatten[Inverse[A]]]; If[min>m,min=m; Print[min]],
  {tries}]; {min,max}];
Do[ Print[{n,N[FindExtrema[n,100000]]}],{n,1,12}]
The maxima and minima grow as follows. For values like n=11,12 we run the experiment for hours to get the larger values. The value min(11)=-135 soon no more extremal. One can bet there is a value -141 too. We let it run for a weekend (actually, the value 148 just appeared on Sunday (Feb 17, 2019) 151 on Monday Feb 18, 2019, so that also 141 was not the maximum yet. Monday also gave 83 for n=10.) The Boolean spaces of matrices are just too huge and the cases with maximal value too sparse to reach in a reasonable time.
n   = {1, 2, 3, 4, 5, 6, 7,  8,  9, 10, 11,   12  }
min = {1,-1,-1,-2,-3,-5,-9,-18,-39,-80,-156,-213  }
max = {1, 1, 1, 2, 3, 5, 9, 18, 38, 94, 151, 213  }
       *  *  *  *  *   
       true  values  |  records so far 
Updates: Obviously, the numbers max(n) and min(n) change monotonically: we can look at the partitioned matrix, where one matrix is a 1x1 matrix and the other a (n 1) x (n-1) matrix. A maximum or minimum for n-1 can now be matched also for n. Note that the Green function entries are not integers in general. They are rational. But the maximum and minimum appear to be integers. We experimentally see that this is the case when the determinant is 1 or -1, which is when the Boolean matrix is unimodular. One can use geometry to generate matrices with large Green function entries. The unimodularity theorem assures that the Boolean matrix encoding the intersections of sets in a finite abstract simplicial complex is always unimodular. The maximal Green function entries are there geometric.
Conjecture: The minimum and maximum Green function value is an integer
Conjecture: The minimum is minus the maximum.
This is so far supported by the fact that in the above numbers, when we saw a difference, we just ran the code again for much longer time to find the lower or higher numbers.
Then there is the question about growth. How fast does this sequence grow? We can explore this by data fitting. It actually appears as if the growth is linear on a logarithmic scale indicated exponential growth. At the beginning at least we see that the maximum max(n) is 2 max(n-1)-1 or max(n)=2 max(n-1).
max = {1, 1, 1, 2, 3, 5, 9, 18, 36, 62, 141,213}
Fit[Log[max],{1,x,x^2},x]
0.0252498 x^2+0.206081 x-0.498099
Boolean Green Function problem

The determinants

We will talk about determinants in the 4th week. The Hadamard maximum determinant problem asks what are the largest possible determinants in a class of random matrices. In the case of Boolean matrices, this leads to the sequence A003432 which is
1, 1, 1, 2, 3, 5, 9, 32, 56, 144, 320, 1458,
Hadamard in 1893 proved that det(A) ≤ sqrt(n^n) if the entries of A are complex number of length ≤ 1. For Boolean matrices there is a better upper bound sqrt((n+1)^(n+1))/2^n. See this reference.

The sum of the matrix entries

The inverse of a matrix has coefficients g(i,j) which are also known as Green functions. They have an interpretation as energies. Now, we can sum them up to get the total energy. Mathematically, what is the sum of the inverse entries? It appears always to be positive.
We are interested in this also because of previous similar work in simplicial complexes. See the energy theorem, where the sum of the Green function matrices is a topological invariant. There is an other angle connected with Counting rooted forests in a graph and Cauchy-Binet. The determinant det(1+L), where L is the Kirchhoff matrix of a graph counts the number of rooted forests. Chebotarev and Shamis also noted that the Green function entries (1+L)-1 are probabilities (this follows readily from Cramer). So, the Green function (1+L)-1 is always a doubly stochastic matrix. By the way, I discovered myself the matrix forest theorem as well as the stochastic property of the Fredholm Matrix 1+L in experiments first, proved it and then found the Chebotarev-Shamis references from 1997. This is very common in mathematical research. If you do research, most of the ``discoveries" made turn out already been done. This is only getting more likely as time goes on as the mathematical knowledge is huge and grows fast. What can be seen in textbooks is most of the time just the tip of an iceberg. Do we have to worry running out of mathematics? Fortunately not. In contrary, every discovery triggers three new questions.

Now, also the question of the Green function entries of a random Boolean matrix raised above could have already been asked and answered. We are currently (Feb 17, 2019), not yet aware of it. By the way, Chebotarev and Shamis are pictured on this mathtable handout from 2016. Here are the pictures of the discoverers of the Matrix Forest Theorem:
Pavel Chebotarev Elena Shamis
The matrix forest theorem which counts the number of forests as det(1+L) is even more elegant than the Cauchy matrix tree theorem which tells that the number of spanning trees is the pseudo determinant Det(L) of L. We might mention the pseudo determinant later in the course. The matrix L is always singular but one can take the product of the non-zero eigenvalues. On the other hand the matrix 1+L is always invertible because the smallest eigenvalue of 1+L is 1. We will talk about eigenvalues later in the course.